
�e�en�mi �lohy jsou nap�. ��sla

$$
x = {\sqrt 2}^{\sqrt 2}, \quad y = \sqrt 2,
$$
proto�e
      $$
            x^y = \left({\sqrt 2}^{\sqrt 2}\right)^{\sqrt 2} =
            \left({\sqrt 2}\right)^2 = 2
      $$

Kdyby n�hodou bylo $x = {\sqrt 2}^{\sqrt 2}$ racion�ln�,
pak m��eme pou��t

$$
x = \sqrt 2 ({\sqrt 2}^{\sqrt 2}), \quad
y = 2(\sqrt 2 -1).
$$

Jin� �e�en� je

$$
x=e, \quad y=\log 2,
$$
ale bude pot� dok�zat, �e jde o racion�ln� ��sla.
