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Vypo�t�te:

$$\lim\limits_{x \to 1} {x^2 -x \over \sqrt{x}-1}$$

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Dan� v�raz roz����me dvoj�lenem $\sqrt{x} + 1$ a dostaneme

$$\lim\limits_{x \to 1} {x^2 -x \over \sqrt{x}-1} = \lim\limits_{x \to 1} {(x^2 -x)(\sqrt{x} +1) \over x-1} = \lim\limits_{x \to 1} x(\sqrt{x} +1) = 2$$


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